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Question: In a triangle ABC, if b = 2, B = 30<sup>0</sup> then the area of circumcircle of triangle ABC in squ...

In a triangle ABC, if b = 2, B = 300 then the area of circumcircle of triangle ABC in square units is –

A

p

B

2p

C

4p

D

6p

Answer

4p

Explanation

Solution

R = b2sinθ=22sin30\frac { \mathrm { b } } { 2 \sin \theta } = \frac { 2 } { 2 \sin 30 ^ { \circ } } = 2

Area of circle = pR2 = 4p