Question

In a triangle ABC, if a = 2, B = 60ŗ and C = 75⁰, then b =

• A. $\sqrt { 3 }$
• B. $\sqrt { 6 }$
• C. $\sqrt { 9 }$
• D. $1 + \sqrt { 2 }$

Answer 1

Answer: (B)

$\sqrt { 6 }$

Answer 2

A + B + C = 180⁰

A = 180⁰ – (B + C)

A = 180⁰ – (60⁰ + 75⁰) = 45⁰

= ⇒$\frac { \sin 45 ^ { \circ } } { \sin 60 ^ { \circ } }$ =

⇒ b = $\frac { 2 \sin 60 ^ { \circ } } { \sin 45 ^ { \circ } }$=$\frac { 2 \sqrt { 3 } } { 2 }$× $\sqrt { 2 }$ = $\sqrt { 6 }$