Question: In a triangle ABC, AD is the altitude from A (fig.). Given b \> c, ŠC = 23<sup>0</sup> and AD = ![](...

Question

In a triangle ABC, AD is the altitude from A (fig.). Given b > c, ŠC = 23⁰ and AD = then ŠB, is equal to –

Answer 1

We have AD = b sin C

Ž $\frac { a b c } { b ^ { 2 } - c ^ { 2 } }$ = b sin C

Ž $\frac { \sin C } { c }$ =

Ž =

Ž sin A =

=

Ž sin (B – C) = 1 [Q sin (B + C) = sin A]

Ž B – C = 90⁰

Ž B = 90⁰ + C = 90⁰ + 23⁰ = 113⁰.