Question

In a triangle ABC, ∠A = 60⁰, ĐB = 40⁰, & ĐC = 80⁰. If P is centre of circumcircle of DABC with unity radius, then the radius of circumcircle of DBPC is

• A. $\sqrt { 3 }$
• B. 2
• C. 1
• D. None

Answer 1

Answer: (C)

1

Answer 2

Let R₁ is circumradius of DBPC

\ $\frac { \mathrm { a } } { \sin 120 ^ { \circ } }$ = 2R₁ ……. (i)

Also for DABC