Question

In a trapezium $ABCD AB || CD$, the diagonals AC and BD intersect at ‘P’. If $AB: CD = 2:1$, then area of $△CPD:$area of $△APB =$

• A. 1:4
• B. 2:1
• C. 1:2
• D. 4:1

Answer 1

Answer: (A)

1:4

Answer 2

The correct answer is option (A):1:4