Question
Question: In a transistor circuit shown in figure, if the base current is \(35\mu A\), then the value of resis...
In a transistor circuit shown in figure, if the base current is 35μA, then the value of resistor Rb is,
A. 257kΩ.
B. 123.5kΩ.
C. 380.05kΩ.
D. None of these.
Solution
Kirchhoff's loop rule states that, in a closed circuit, the sum of all the voltages is equal to zero. The sign while applying the Kirchhoff’s loop rule depends upon the direction in which we move while considering all the voltages.
Step by step solution:
Step 1.
It is given that the base current is 35μA in the above circuit and the battery is of9V.
Step 2.
Apply Kirchhoff’s rule in the circuit above,
Here the direction is along the flow of current; therefore there will be voltage drop as current flows from high voltage towards low voltage. The sum of
According to Kirchhoff’s rule,
{I_b} \cdot {R_b} = 9 \\
{R_b} = \dfrac{9}{{{I_b}}} \\
{R_b} = \dfrac{9}{{35 \times {{10}^{ - 6}}}} \\
{R_b} = 257.143 \times {10^3}\Omega \\
{R_b} \approx 257k\Omega \\