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Question

Physics Question on Transistors

In a transistor amplifier, β=62\beta = 62, RL=5000ΩR_L = 5000\,\Omega and input resistance of the transistor is 500Ω500\, \Omega. What is power amplification ?

A

62006200

B

4585045850

C

3844038440

D

1532015320

Answer

3844038440

Explanation

Solution

Given:β=62,RL=5000Ω,Ri=500ΩGiven : \beta = 62, R_{L} = 5000 \,\Omega, R_{i} = 500\,\Omega Power amplification, AP=β2RLRi=(62)2×5000500=38440A_{P} = \beta^{2} \cdot\frac{R_{L}}{R_{i}} = \left(62\right)^{2} \times\frac{5000}{500} = 38440