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Question

Physics Question on Alternating current

In a transformer the number of primary turns is four times that of the secondary turns. Its primary is connected to an ACAC source of voltage VV. Then,

A

Current through its secondary is about four times that of the current through its primary

B

Voltage across its secondary is about four times that of the voltage across its primary

C

Voltage across its secondary is about two times that of the voltage across its primary

D

Voltage across its secondary is about times that of the voltage across its primary

Answer

Current through its secondary is about four times that of the current through its primary

Explanation

Solution

For a transformer, ratio of voltages in primary and secondary can be written as
V1V2=N1N2=I2I1\frac{V_{1}}{V_{2}}=\frac{N_{1}}{N_{2}}=\frac{I_{2}}{I_{1}}
I2I1=4N2N2=4\Rightarrow \frac{I_{2}}{I_{1}}=\frac{4 N_{2}}{N_{2}}=4
I2=4I1\Rightarrow I_{2}=4 I_{1}