Question

In a transformer, number of turns in the primary are 140 and that in the secondary are 280 . If current in primary is $4 A$, then that in the secondary is :

• A. $4 A$
• B. $2 A$
• C. $6 A$
• D. $10 A$

Answer 1

Answer: (B)

$2 A$

Answer 2

Given $: i_{p}=4 A ,\,\,\,\, N_{p}=140, N_{s}=280$ From the formula $\frac{i_{p}}{i_{s}}=\frac{N_{s}}{N_{p}}$ or $\frac{4}{i_{s}}=\frac{280}{140}$ So, $i_{s}=2 A$