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Question: In a traingle ABC, if r<sub>1</sub> = 1, r<sub>2</sub> = 2, C = π/2 then ∆ =...

In a traingle ABC, if r1 = 1, r2 = 2, C = π/2 then ∆ =

A

1

B

3/2

C

2

D

5/2

Answer

2

Explanation

Solution

r – a = ∆, r – b = Δ2\frac{\Delta}{2} ⇒ c = 3Δ2\frac{3\Delta}{2}, b – a = Δ2\frac{\Delta}{2}

c2 – (b – a)2 = 2∆2 ⇒ ∆ = 2