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Question: In a toss of two dice, A throws a total of 5. The probability that he will throw another 5 before he...

In a toss of two dice, A throws a total of 5. The probability that he will throw another 5 before he throws 10 is

A

4/7

B

3/5

C

7/10

D

None of these

Answer

4/7

Explanation

Solution

19+(1−736)⋅19+………∞=47\frac { 1 } { 9 } + \left( 1 - \frac { 7 } { 36 } \right) \cdot \frac { 1 } { 9 } + \ldots \ldots \ldots \infty = \frac { 4 } { 7 }