Question

In a symmetric matrix of order ‘12’ maximum number of different elements are –

• A. 78
• B. 144
• C. 136
• D. None

Answer 1

Answer: (A)

78

Answer 2

Maximum no. of different elements = $\frac{n^{2} + n}{2}$

= $\frac{144 + 12}{2}$ = $\frac{156}{2}$ = 78