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Question

Physics Question on communication systems

In a superheterodyne receiver, the IF is 455 kHz. If it is tuned 1200 kHz, the image frequency will be

A

1562 kHz

B

1675 kHz

C

2110 kHz

D

2025 kHz

Answer

2110 kHz

Explanation

Solution

Given fi=455kHzf _{ i }=455 \,kHz fs=1200kHzf _{ s }=1200\, kHz \therefore Image frequency =fs+2fi= f _{ s }+2 f _{ i } =1200+2×455=1200+2 \times 455 =2110kHz=2110 \,kHz