Question

In a ₉₂U²³⁵ reactor, it takes 30 days to use up 2 kg of fuel. If each fission gives 185 MeV of usable energy, then power output of reactor is –

• A. 5.85 × 10⁷ watt
• B. 1.52 × 10¹⁴ watt
• C. 5.07 × 10¹² watt
• D. 3.82 × 10⁶ watt

Answer 1

Answer: (A)

5.85 × 10⁷ watt

Answer 2

185 MeV = 2.96 × 10^–11 Joule

P = = $\frac { 2.96 \times 10 ^ { - 11 } \times \frac { 6.022 \times 10 ^ { 23 } } { 0.235 } \times 2 } { 30 \times 24 \times 3600 }$

= 5.85 × 10⁷ watt