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Question

Physics Question on Alternating current

In a step up transformer the turn ratio is 1 : 10. A resistance of 200Ω200\,\Omega connected across the secondary is drawing a current of 0.5 A. What is the primary voltage and current?

A

50 V, 1 A

B

10 V, 5 A

C

25 V, 4 A

D

20 V, 2 A

Answer

10 V, 5 A

Explanation

Solution

Given, Np:Ns=1:10{{N}_{p}}:{{N}_{s}}=1:10 Vs=Is×R{{V}_{s}}={{I}_{s}}\times R =0.5×200=100volt=0.5\times 200=100\,\,volt Vp=?,Ip=?{{V}_{p}}=?,{{I}_{p}}=? Transformation ratio k=NsNp=VsVp=IpIsk=\frac{{{N}_{s}}}{{{N}_{p}}}=\frac{{{V}_{s}}}{{{V}_{p}}}=\frac{{{I}_{p}}}{{{I}_{s}}} \therefore 101=100Vp\frac{10}{1}=\frac{100}{{{V}_{p}}} Vp=10volt{{V}_{p}}=10\,\,volt Again, 101=Ip0.5\frac{10}{1}=\frac{{{I}_{p}}}{0.5} Ip=5A{{I}_{p}}=5\,\,A