Question
Question: In a square cut, the speed of the cricket ball changes from 30 \[m{{s}^{-1}}\] to 40 \[m{{s}^{-1}}\]...
In a square cut, the speed of the cricket ball changes from 30 ms−1 to 40 ms−1 during the time of its contact Δt=0.01s with the bat. If the ball is deflected by the bat through an angle of θ=900, find the magnitude of the average acceleration of the ball (in ×102ms−2) during the square cut.
Solution
We need to understand the impact caused by the batsman on the ball during the square-cut strike on the ball. The change in velocity of the ball is due to the impulse on the ball as the man hits it with the bat with his muscle power resulting in an acceleration.
Complete step-by-step solution
We know that in the game of cricket, a bowler throws a ball at the batsman with a speed. The ball reaching the batsman with a velocity is hit by the batsman with his bat. The hitting is often associated with a deviation of the ball towards another side with an increase in the velocity of the ball.
In our situation, the batsman strikes the ball coming with an initial velocity of 30ms−1, deviates into a angle of θ=900 and the velocity of the ball is increased to 40 ms−1.
We know that the average acceleration of a body is defined as the ratio of change in velocity to the time taken for this change. Here, the bat has a contact time of Δt=0.01s with the ball. So, we can easily find the average acceleration of the ball as –