Question

In a single throw of two dice, the probability of getting more than 7 is

• A. $\frac { 7 } { 36 }$
• B. $\frac { 7 } { 12 }$
• C. $\frac { 5 } { 12 }$
• D. $\frac { 5 } { 36 }$

Answer 1

Answer: (C)

$\frac { 5 } { 12 }$

Answer 2

Required probability is

$P ($ getting $8 ) + P ( 9 ) + P ( 10 ) + P ( 11 ) + P ( 12 )$

$= \frac { 5 } { 36 } + \frac { 4 } { 36 } + \frac { 3 } { 36 } + \frac { 2 } { 36 } + \frac { 1 } { 36 } = \frac { 15 } { 36 } = \frac { 5 } { 12 }$ .