Question

In a simultaneous throw of a pair of dice, the probability of getting a total more than 7 is

• A. $\frac{7}{12}$
• B. $\frac{5}{36}$
• C. $\frac{5}{12}$
• D. $\frac{7}{36}$

Answer 1

Answer: (C)

$\frac{5}{12}$

Answer 2

Let E be an event of getting a total score of > 7
$E = {(2, 6), (3, 5), (3, 6), (4, 4), (4, 5), (4, 6), (5, 3), (5, 4), (5, 5), (5, 6), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}$
$\therefore\, P(E) =\frac{n(E)}{n(S)} = \frac{15}{36} = \frac{5}{12}$