Question

In a simple cubic lattice of anions, the side length of the unit cell is 2.88 Å. The diameter of the void in the body centre is

• A. 1.934 Å
• B. 0.461 Å
• C. 2.108 Å
• D. 4.988 Å

Answer 1

Answer: (C)

2.108 Å

Answer 2

for (bcc) = r+/r– = 0.732 and a =$\frac{2(r^{+} + r^{-})}{\sqrt{3}}$

and diameter of cubical void (2r+) = a($\sqrt{3}$–1)

= 2.888 × 0.732 = 2.108 Å.