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Question

Physics Question on work, energy and power

In a shotput event an athlete throws the shotput of mass 10kg10\, kg with an initial speed of 1m/s1 \,m/s at 45?45^? from a height 1.5m1.5 \,m above ground. Assuming air resistance to be negligible and acceleration due to gravity to be 10m/s210\, m/s^2, the kinetic energy of the shotput when it just reaches the ground will be

A

2.5J2.5\,J

B

5.0J5.0\,J

C

52.5J52.5\,J

D

155.0J155.0\,J

Answer

155.0J155.0\,J

Explanation

Solution

Initial KEKE of the shotput =12(10kg)(1m/s2)=5J= \frac{1}{2}\left(10\,kg\right)\,\left(1\,m/s^{2}\right) = 5\,J Initial PEPE of the shotput at a height 1.5m1.5\, m above ground =mgh=(10kg)(10m/s2)(1.5m)=150J= mgh = (10 \,kg) \,(10 \,m/s^2)\, (1.5\, m) = 150\, J Total initial energy of the shotput =155J= 155 \,J Since air resistance is negligible and final potential of the shotput as it hits the ground (h=0)(h = 0) is zero, kinetic energy of the shotput on hitting the ground =155J= 155\, J