Question

In a series LR circuit $X_L=R$ and power factor of the circuit is $P _1$ When capacitor with capacitance $C$ such that $X _{ L }= X _{ C }$ is put in series, the power factor becomes $P _2$ The ratio $\frac{ P _1}{ P _2}$ is

• A. $\frac{1}{2}$
• B. $\frac{1}{\sqrt{2}}$
• C. $\frac{\sqrt{3}}{\sqrt{2}}$
• D. $2: 1$

Answer 1

Answer: (B)

$\frac{1}{\sqrt{2}}$

Answer 2

The correct option is(B): $\frac{1}{\sqrt{2}}$.