Question

In a series LCR Circuit, the value of resistance as well as (XL - XC) is halved, then the new current amplitude (I2) will satisfy: (I1 is old current amplitude)

• A. I2 = 2I1
• B. I2 = 0
• C. $l_2=\frac{l_1}{2}$
• D. I2 = I1

Answer 1

Answer: (A)

I2 = 2I1

Answer 2

The Correct answer is option is (A) : I2 = 2I1