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Question

Physics Question on Alternating current

In a series LCR circuit, the inductance L is 10 mH, Capacitance C is 1μF and resistance R is 100Ω. The frequency at which resonance occurs is

A

1.59 kHz

B

15.9 rad/s

C

15.9 kHz

D

1.59 rad/s

Answer

1.59 kHz

Explanation

Solution

The correct option is (A): 1.59 kHz
The resonant frequency (fr) of a series LCR circuit is given by the formula:
fr = 12π(LC)\frac{1}{2\pi(LC)}
where L is the inductance in Henries, C is the capacitance in farads, and π is the mathematical constant pi (approximately equal to 3.14).
Substituting the given values, we get:
fr=12π10mH×1μFf_r=\frac{1}{2\pi\sqrt{10\,mH\times1\mu F}}
=1(2π(10x103Hx106F))= \frac{1}{(2π\sqrt{(10 x 10-3 H x 10-6 F)) }}
=1(2π(108))= \frac{1}{(2π\sqrt{(10-8))}}
=1(2π×104)=\frac{1}{(2π \times 10^{-4})}
=1(6.28×105)= \frac{1}{(6.28 \times 10^{-5})}
= 1591.5 Hz (approx)
Therefore, the resonant frequency of the series LCR circuit is approximately 1591.5 Hz, = 1.59K Hz