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Question: In a series combination of resistances (A) Potential difference is same across each resistance (...

In a series combination of resistances
(A) Potential difference is same across each resistance
(B) Total resistance is reduced
(C) Current is same in each resistance
(D) All above are true.

Explanation

Solution

Hint : Equivalent resistance of a series arrangement of resistor is the sum of the individual resistances in the circuit. On applying Kirchhoff's voltage rule around a loop with resistors in series, and investigating the result we will find the correct option.

Formula used: In this solution we will be using the following formula;
Rs=R1+R2+...+Rn{R_s} = {R_1} + {R_2} + ... + {R_n} where Rs{R_s} is the equivalent resistance of a series arrangement of resistors, and R1...Rn{R_1}...{R_n} are the individual resistances of the resistors.
V=0\sum V = 0 where VV are the individual voltage drop across the elements in a circuit.
V=IRV = IR where II is the current through a resistor, and RR is the resistance of the resistor.

Complete step by step answer
Let us assume that two resistors are placed in series to a voltage source. The voltage drop across each resistor is given by the Ohms law as
V=IRV = IR where VV is the voltage, II is the current through a resistor, and RR is the resistance of the resistor.
Hence, applying the Kirchhoff’s voltage law around the circuit, we have
VI1R1I2R2=0V - {I_1}{R_1} - {I_2}{R_2} = 0
V=I1R1+I2R2\Rightarrow V = {I_1}{R_1} + {I_2}{R_2}
The voltage VV can be written as
V=IsRsV = {I_s}{R_s}
Hence, IsRs=I1R1+I2R2{I_s}{R_s} = {I_1}{R_1} + {I_2}{R_2}
Now, we know that the equivalent resistance of a series arrangement of resistors is given as
Rs=R1+R2+...+Rn{R_s} = {R_1} + {R_2} + ... + {R_n} , where R1...Rn{R_1}...{R_n} are the individual resistances of the resistors. Hence, for the two resistors in series we assumed, we have
Rs=R1+R2{R_s} = {R_1} + {R_2}
Hence, from IsRs=I1R1+I2R2{I_s}{R_s} = {I_1}{R_1} + {I_2}{R_2} we can get the equivalent resistance formula by making
Is=I1=I2{I_s} = {I_1} = {I_2}
Hence, the current flowing through a series combination of resistors is the same in each resistor.
Thus, the correct option is C.

Note
In actuality, the current through each resistance in a series combination is obtained from the Kirchhoff’s current law, which in turn is obtained from the principle of conservation of charge. From the current law, we know that the current flowing into a node is the same as the current flowing out the node. Hence, since in a series combination, there are no branches, then the current flowing out one resistor must be equal to the current flowing into the next one.