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Question: In a series circuit R = 300 Ω, L = 0.9 H, C = 2.0 μF and ω = 1000 rad/sec. The impedance of the circ...

In a series circuit R = 300 Ω, L = 0.9 H, C = 2.0 μF and ω = 1000 rad/sec. The impedance of the circuit is

A

1300 Ω

B

900 Ω

C

500 Ω

D

400 Ω

Answer

500 Ω

Explanation

Solution

For series R-L-C circuit,

Z=R2+(XLXC)2Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}

=(300)2+(1000×0.91061000×2)2=500Ω= \sqrt{(300)^{2} + \left( 1000 \times 0.9 - \frac{10^{6}}{1000 \times 2} \right)^{2}} = 500\Omega