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Question: In a screw gauge, there are 50 divisions on its cap and pitch of screw is 1 mm. When a wire is place...

In a screw gauge, there are 50 divisions on its cap and pitch of screw is 1 mm. When a wire is placed between studs then it gives 3 divisions on main scale and 15 circular scale division coincides with base line. Diameter of the wire is-

A

1.80 mm

B

3.30 mm

C

3.15 mm

D

None

Answer

3.30 mm

Explanation

Solution

LC = 150\frac { 1 } { 50 } = .02 mm ; MSR = 3 × 1 mm = 3 mm

CSR⁡=15×.02=.30 mm\operatorname { CSR } = 15 \times .02 = .30 \mathrm {~mm} ; Diameter of wire =3.30 mm= 3.30 \mathrm {~mm}