Question
Question: In a saturated solution of the sparingly soluble strong electrolyte \(AgI{O_3}\)(Molecular mass = 28...
In a saturated solution of the sparingly soluble strong electrolyte AgIO3(Molecular mass = 283) the equilibrium which sets in is
AgIO3(s)⇌Ag+(aq)+IO3−(aq)
If the solubility product constant Kspof AgIO3 at a given temperature is 1.0×10−8, what is the mass of AgIO3 contained in 100 ml of its saturated solution ?
a) 28.3×10−2g
b) 2.83×10−3g
c) 1.0×10−7g
d) 1.0×10−4g
Solution
The solubility product constant gives us the product of the solubility of all components in a solution. In case of AgIO3, it can be given by the formula -
Ksp=[Ag+][IO3−]
Complete answer:
First, let us write what is given to us and what we need to find out.
Given :
Solubility product constant (Ksp) of AgIO3= 1.0×10−8
Volume of saturated solution = 100 ml
Molecular mass = 283
To find :
mass of AgIO3
We know that Ksp of solution is given by -
Ksp=[Ag+][IO3−]
If we say that ‘s’ is the solubility of electrolyte
So, [Ag+]=[IO3−]=[AgIO3]= s
Thus, Ksp= (s) (s)
Ksp=s2
s2= 1.0×10−8
‘s’ = 1.0×10−4M
So, 1000 ml of solution will have electrolyte = 1.0×10−4moles
And we have a solution of 100 ml.
Thus, 100 ml of solution will have electrolyte =1.0×10−5moles
We have molar mass = 283 g/mol
So, the mass of electrolyte in 100 ml solution = 1.0×10−5×283
mass of electrolyte in 100 ml solution = 2.83×10−3g
So, this is our answer.
Thus, the correct option is option b.).
Note:
The saturated solution is the one which has dissolved the maximum amount of solute. It can not dissolve more solute. Thus, it has the maximum number of moles of an electrolyte that can be present. While the unsaturated solution is one which can dissolve more solute.