Question

In a saturated solution of the sparingly soluble strong electrolyte AgIO3 (Molecular mass = 283) the equilibrium which sets in is

AgIO3(s) $\rightleftharpoons$ Ag+(aq) + IO–3(aq)

If the solubility product constant Ksp of AgIO3 at a given temperature is 1.0 × 10–8, what is the mass of AgIO3 contained in 100 ml of its saturated solution?

• A. 1.0 × 10–7 g
• B. 1.0 × 10–4 g
• C. 28.3 × 10–2 g
• D. 2.83 × 10–3 g

Answer 1

Answer: (D)

2.83 × 10–3 g

Answer 2

AgIO3(s) $\rightleftharpoons$ Ag+(aq) + IO–3(aq) [s = Solubility]

[s = foys;rk] Ksp = s2

or s = 1.0 × 10–4 mol/lit = 1.0 × 10–4 × 283 g/lt = 2.83 × 10–3 gm/100 ml.