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Question: In a satellite if the time of revolution is T, then K.E. is proportional to...

In a satellite if the time of revolution is T, then K.E. is proportional to

A

1T\frac { 1 } { T }

B

1T2\frac { 1 } { T ^ { 2 } }

C

1T3\frac { 1 } { T ^ { 3 } }

D

T−2/3T ^ { - 2 / 3 }

Answer

T−2/3T ^ { - 2 / 3 }

Explanation

Solution

v =GMr= \sqrt { \frac { G M } { r } } ∴ and T2∝r3T ^ { 2 } \propto r ^ { 3 }

∴K.E.∝T−2/3K . E . \propto T ^ { - 2 / 3 }