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Question

Physics Question on Gravitation

In a satellite, if the time of revolution is TT , then KEKE is proportional to

A

1T\frac{1}{T}

B

1T2\frac{1}{T^2}

C

1T3\frac{1}{T^3}

D

T2/3T^{-2/3}

Answer

T2/3T^{-2/3}

Explanation

Solution

Velocity of satellite v=GMrv=\sqrt{\frac{G M}{r}} KEv21r\therefore KE \propto v^{2} \propto \frac{1}{r} and T2r3T^{2} \propto r^{3} KET2/3\therefore KE \propto T^{-2 / 3}