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Question

Physics Question on Atoms

In a Rutherford scattering experiment when a projectile of charge Z1Z _{1} and mass M1M _{1} approaches a target nucleus of charge Z2Z _{2} and mass M2M _{2}, the distance of closest approach is r0r _{0}. The energy of the projectile is :

A

Directly proportional to z1z2z_1 z_2

B

Inversely proportional to z1z_1

C

Directly proportional to mass M1M_1

D

Directly proportional to M1×M2M_1 \times M_2

Answer

Directly proportional to z1z2z_1 z_2

Explanation

Solution

Energy of the projectile is the potential energy at closest approach, =14π0Z1Z2r0=\frac{1}{4 \pi \in_{0}} \frac{ Z _{1} Z _{2}}{ r _{0}} Therefore energy z1z2.z_1 z_2.