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Question: In a room where the temperature is 30<sup>o</sup>C, a body cools from 61<sup>o</sup>C to 59<sup>o</s...

In a room where the temperature is 30oC, a body cools from 61oC to 59oC is 4 minutes. The time taken by the body to cool from 51oC to 49oC will be:

A

4 minutes

B

6 minutes

C

5 minutes

D

8 minutes

Answer

6 minutes

Explanation

Solution

Rate of cooling α\alpha difference in temperature

in first case

Δθ=6030=30\Delta \theta = 60 - 30 = 30

dt = 4 minute

\therefore

For second case

∆θ = 50 − 30 = 20

\therefore