Question

In a resonance tube experiment the first resonance is obtained at 10 cm of air column and the second for 32 cm, the end correction is –

• A. 0.5 cm
• B. 1 cm
• C. 1.5 cm
• D. 2 cm

Answer 1

Answer: (B)

1 cm

Answer 2

e = $\frac { \ell _ { 2 } - 3 \ell _ { 1 } } { 2 } = \frac { 32 - 3 \times 10 } { 2 }$ = 1 cm