Question

In a resonance pipe the first and second resonance are obtained at lengths 22.7 cm and 70.2 cm respectively. What will be the end correction -

• A. 1.05 cm
• B. 115.5 cm
• C. 92.5 cm
• D. 113.5 cm

Answer 1

Answer: (A)

1.05 cm

Answer 2

e = $\frac{\mathcal{l}_{2}–3\mathcal{l}_{1}}{2}$

e = $\frac{70.2–3 \times 22.7}{2}$ = $\frac{70.2–68.1}{2}$ = $\frac{2.1}{2}$

= 1.05 cm