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Question

Physics Question on Oscillations

In a resonace air column experiment, first and second resonances are obtained at lengths of air columns l1l_1 and l2 l_2, the third resonance will be obtained at a length of

A

2l2l12l_2-l_1

B

l22l+1l_2-2l+1

C

l2l1l_2-l_1

D

3l2l13l_2-l_1

Answer

2l2l12l_2-l_1

Explanation

Solution

l1+e=λ4l_1 +e = \frac{\lambda}{4} \Rightarrow (1) l2+e=3λ4l_2 + e = \frac{3 \lambda}{4} \Rightarrow (2) from (1) , (2) sub e, λ\lambda in l3+e=5λ4l_3 + e = \frac{5 \lambda}{4}