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Question: In a region of uniform magnetic induction B = 10<sup>– 2</sup>Tesla, a circular coil of radius 30 cm...

In a region of uniform magnetic induction B = 10– 2Tesla, a circular coil of radius 30 cm and resistance π2 ohm is rotated about an axis which is perpendicular to the direction of B and which forms a diameter of the coil. If the coil rotates at 200 rpm the amplitude of the alternating current induced in the coil is

A

2Ma

B

30 Ma

C

6 Ma

D

200 Ma

Answer

6 Ma

Explanation

Solution

i0=BANωR=102×π×(30×102)2×1×2π×200π2×60=6×103A=6mA.i_{0} = \frac{BAN\omega}{R} = \frac{10^{- 2} \times \pi \times (30 \times 10^{- 2})^{2} \times 1 \times 2\pi \times 200}{\pi^{2} \times 60} = 6 \times 10^{- 3}A = 6mA.