Question

In a reaction P + Q$\rightarrow$ R + S, there is no change in entropy. Enthalpy change for the reaction ($\Delta H$) is $12kJmol^{- 1}$Under what conditions, reaction will have negative value of free energy change?

• A. If $\Delta H$ is positive.
• B. If $\Delta H$ is negative.
• C. If $\Delta H$ is 24 $kJmol^{- 1}$
• D. If temperature of reaction is high.

Answer 1

Answer: (B)

If $\Delta H$ is negative.

Answer 2

: $\Delta G = \Delta H - T\Delta S,\Delta S = 0$ or $T\Delta S = 0\Delta G = \Delta H$