Question

In a reaction, if half of the double bond is broken and two new bonds are formed, this is a case of.

• A. Elimination
• B. Addition
• C. Displacement
• D. Rearrangement

Answer 1

Answer: (B)

Addition

Answer 2

E.g. $CH_{2} = CH_{2} + Br_{2} \rightarrow \underset{\underset{Br}{|}\underset{Br}{|}}{CH_{2} - CH_{2}}$

Half of the double bond is broken. It means $\pi$bond is broken while sigma bond is retained also two new $C - Br$ bonds are formed.