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Question: In a reaction \[CH_{2} = CH_{2}\underset{acid}{\overset{\quad\text{Hypochlorous}\quad}{\rightarrow}...

In a reaction

CH_{2} & - & OH \\ | & & \\ CH_{2} & - & OH \end{matrix}$$ Where M = molecule; R = reagent M and R are.
A

CH3CH2ClCH_{3}CH_{2}Cl and NaOH

B

CH2ClCH2OHCH_{2}Cl - CH_{2}OH and aq. NaHCO3\text{aq. }NaHCO_{3}

C

CH3CH2OHCH_{3}CH_{2}OH and HCl

D

CH2=CH2CH_{2} = CH_{2} and heat

Answer

CH2ClCH2OHCH_{2}Cl - CH_{2}OH and aq. NaHCO3\text{aq. }NaHCO_{3}

Explanation

Solution

CH2=CH2HOClCH2ClCH2OHaqNaHCO3CH_{2} = CH_{2}\overset{\quad HOCl\quad}{\rightarrow}\underset{\underset{Cl}{|}}{CH_{2}} - \underset{\underset{OH}{|}}{CH_{2}}\overset{\quad aqNaHCO_{3}\quad}{\rightarrow}

CH2OHCH2OHGlycol\underset{\text{Glycol}}{\underset{\underset{CH_{2} - OH}{|}}{CH_{2} - OH}}