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Question: In a reaction \(2X \rightarrow Y\) the concentration of X decreases from \(3.0\)moles/litre to \(2.0...

In a reaction 2X→Y2X \rightarrow Y the concentration of X decreases from 3.03.0moles/litre to 2.0moles/litre2.0moles/litre in 5 minutes. The rate of reaction is

A

0.1molL−1min⁡−10.1molL^{- 1}\min^{- 1}{}

B

5molL−1min⁡−15molL^{- 1}\min^{- 1}{}

C

1molL−1min⁡−11molL^{- 1}\min^{- 1}{}

D

0.5molL−1min⁡−10.5molL^{- 1}\min^{- 1}{}

Answer

0.1molL−1min⁡−10.1molL^{- 1}\min^{- 1}{}

Explanation

Solution

Rate=−12Δ[X]Δt=−12(3−2)5=−0.1molL−1min⁡−1Rate = - \frac{1}{2}\frac{\Delta\lbrack X\rbrack}{\Delta t} = - \frac{1}{2}\frac{(3 - 2)}{5} = - 0.1molL^{- 1}\min^{- 1}{}negative sign signifies the decrease in concentration.