Question
Question: In a radioactive series, <sub>92</sub>U<sup>238</sup> changes to <sub>82</sub>Pb<sup>206</sup> throu...
In a radioactive series, 92U238 changes to 82Pb206 through n1a-decay process and n2b-decay process-
A
n1 = 8, n2 = 8
B
n1 = 6, n2 = 6
C
n1 = 8, n2 = 6
D
n1 = 6, n2 = 8
Answer
n1 = 8, n2 = 6
Explanation
Solution
92U238 ® 82Pb206 + n1 2a4 + n2 –1e0
4n1 + 0 × n2 + 206 = 238
n1 = 8
92 = 82 + 2n1 – n2
10 = 2 × 8 – n2
n2 = 6