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Question: In a radioactive series, <sub>92</sub>U<sup>238</sup> changes to <sub>82</sub>Pb<sup>206</sup> throu...

In a radioactive series, 92U238 changes to 82Pb206 through n1a-decay process and n2b-decay process-

A

n1 = 8, n2 = 8

B

n1 = 6, n2 = 6

C

n1 = 8, n2 = 6

D

n1 = 6, n2 = 8

Answer

n1 = 8, n2 = 6

Explanation

Solution

92U238 ® 82Pb206 + n1 2a4 + n2 –1e0

4n1 + 0 × n2 + 206 = 238

n1 = 8

92 = 82 + 2n1 – n2

10 = 2 × 8 – n2

n2 = 6