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Question

Physics Question on Alternating current

In a pure inductive AC circuit

A

current leads the voltage by π2 \frac{ \pi}{ 2}

B

current lags behind the voltage by π2 \frac{ \pi}{ 2}

C

voltage lags behind the current by π\pi

D

current and voltage are in same phase

Answer

current lags behind the voltage by π2 \frac{ \pi}{ 2}

Explanation

Solution

In a pure inductive AC circuit,
E=E0sinωtE = E_0 \sin \, \omega t
i=I0sin(ωtπ2)i = I_0 \sin \, \bigg( \omega t - \frac{ \pi}{ 2} \bigg)
we get ϕ=π2\phi = \frac{ \pi}{ 2}