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Question

Chemistry Question on Chemical Kinetics

In a pseudo first order hydrolysis of ester in water, the following results were obtained. What will be the average rate of reaction between the time interval 3030 to 6060 seconds?

A

1.91×10−21.91\times10^{-2} s−1s^{-1}

B

4.67×10−3molL−1s−14.67\times10^{-3} mol L^{-1} s^{-1}

C

1.98×10−31.98\times10^{-3} s−1s^{-1}

D

2.07×10−22.07\times10^{-2} s−1s^{-1}

Answer

4.67×10−3molL−1s−14.67\times10^{-3} mol L^{-1} s^{-1}

Explanation

Solution

Average rate during the time interval 30−60 s30-60 \,s. Rate=−C2−C1t2−t1-\frac{C_{2}-C_{1}}{t_{2}-t_{1}} =−(0.17−0.31)60−30=-\frac{\left(0.17-0.31\right)}{60-30} =0.4130=\frac{0.41}{30} =4.67×10−3=4.67\times10^{-3} mol L−1mol\,L^{-1} s−1s^{-1}