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Question

Physics Question on kinetic theory

In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT=KVT = K, where KK is a constant. In this process the temperature of the gas is incresed by ΔT\Delta T. The amount of heat absorbed by gas is (R is gas constant) :

A

12RΔT\frac{1}{2} R \Delta T

B

32RΔT\frac{3}{2} R \Delta T

C

12KRΔT\frac{1}{2} K R \Delta T

D

2K3ΔT\frac{2K}{3} \Delta T

Answer

12RΔT\frac{1}{2} R \Delta T

Explanation

Solution

VT=KVT =K
V(PVnR)=kPV2=K\Rightarrow V\left(\frac{PV}{nR}\right) =k \Rightarrow PV^{2} = K
C=R1x+CV\because C = \frac{R}{1-x} +C_{V} (For polytropic process)
C=R12+3R2=R2C = \frac{R}{1-2} + \frac{3R}{2} = \frac{R}{2}
ΔQ=nCΔT\therefore \Delta Q = nC \Delta T
=R2×ΔT= \frac{R}{2} \times\Delta T