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Question: In a ∆ PQR, ∠ R = \(\frac{\pi}{2}\). If tan \(\left( \frac{P}{2} \right)\) and tan \(\left( \frac{Q}...

In a ∆ PQR, ∠ R = π2\frac{\pi}{2}. If tan (P2)\left( \frac{P}{2} \right) and tan (Q2)\left( \frac{Q}{2} \right)are the roots of the equation ax2 + bx + c = 0 (a ≠ 0), then

A

a + b = c

B

b + c = 0

C

a + c = b

D

b = c

Answer

a + b = c

Explanation

Solution

P2\frac{P}{2}+ Q2\frac{Q}{2}= π4\frac{\pi}{4}

∴ tan (P2+Q2)\left( \frac{P}{2} + \frac{Q}{2} \right)= tan π4\frac{\pi}{4}tanP2+tanQ21tanP2tanQ2\frac{\tan\frac{P}{2} + \tan\frac{Q}{2}}{1 - \tan\frac{P}{2}\tan\frac{Q}{2}}= 1

ba1ca\frac{\frac{- b}{a}}{1 - \frac{c}{a}}= 1 ⇒ a + b = c