Solveeit Logo

Question

Physics Question on Current electricity

In a potentiometer experiment, the balancing point with a cell is at a length 240 cm. On shunting the cell with a resistance of 2 Ω\Omega, the balancing length becomes 120 cm. The internal resistance of the cell is

A

1Ω1\, \Omega

B

4Ω4\, \Omega

C

0.5Ω0.5\,\Omega

D

2Ω2\,\Omega

Answer

2Ω2\,\Omega

Explanation

Solution

Internal resistance of a cell is R (122)=2(240120120)=2Ω\quad\left(\frac{\ell_{1}-\ell_{2}}{\ell_{2}}\right)=2 \left(\frac{240-120}{120}\right)=2 \Omega