Question
Question: In a potentiometer arrangement, a cell of emf \[1.25\,{\text{V}}\] gives a balance point at \[35\,{\...
In a potentiometer arrangement, a cell of emf 1.25V gives a balance point at 35cm length of the wire. If the cell is replaced by another cell, the balance point shifts to 63cm, then the emf of second cell is
A. 4.25V
B. 2.25V
C. 3.25V
D. 1.25V
Solution
Use the formula for the balancing condition for a potentiometer. This formula gives the relation between emf of the first cell and its corresponding balancing length and emf of the second cell and its balancing length. Substitute all the values in the equation and calculate the emf of the second cell.
Formula used:
The balance condition for a potentiometer is given by
L1E1=L2E2 …… (1)
Here, E1 is the emf of the first cell, E2 is the emf of the second cell, L1 is the balancing length for the first cell and L2 is the balancing length for the second cell.
Complete step by step answer:
We have given that for the first cell of emf 1.25V the balancing length is 35cm.
E1=1.25V
L1=35cm
We have also given that the balancing length for the second cell is 63cm.
L2=63cm
We can determine the emf of the second cell using equation (1).
Rearrange equation (1) for the emf E2 of the second cell.
E2=L1E1L2
Substitute 1.25V for E1, 35cm for L1 and 63cm for L2 in the above equation.
E2=35cm(1.25V)(63cm)
⇒E2=2.25V
Therefore, the emf of the second cell to have the given value of balancing length must be 2.25V.
So, the correct answer is “Option B”.
Note:
If one attempts to convert the units of balancing lengths of the two cells in the SI system of units, it is a total waste of time. This is because the units of the two balancing length terms get cancelled when the substitution is done. The only thing one should keep in mind that the units of two balancing lengths should be the same for getting them cancelled.