Question

In a PNP transistor working as a common-base amplifier, current gain is 0.96 and emitter current is 7.2 mA. The base current is

• A. 0.4 mA
• B. 0.2 Ma
• C. 0.29 mA
• D. 0.35 mA

Answer 1

Answer: (C)

0.29 mA

Answer 2

$\alpha = \frac{i_{c}}{i_{e}}$=0.96 and i_e = 7.2 mA

$\Rightarrow i_{c} = 0.96 \times i_{e}$= 0.96 × 7.2 = 6.91 mA

$\therefore i_{e} = i_{c} + i_{b}$⇒ 7.2 = 6.91 + i_b ⇒ i_b = 0.29 mA.