Question

In a plane electromagnetic wave traveling in free space, the electric field component oscillates sinusoidally at a frequency of 2x1010 Hz and amplitude of 48 Vm-1. Then the amplitude of the oscillating magnetic field is: (Speed of light in free space = 3x108 ms-1)

• A. 1.6 × 10-6 T
• B. 1.6 × 10-9 T
• C. 1.6 × 10-8 T
• D. 1.6 × 10-7 T

Answer 1

Answer: (D)

1.6 × 10-7 T

Answer 2

Given :
$C=\frac{E_0}{B_0}$
$B_0=\frac{E_0}{C}$
Then,
$=\frac{48}{3\times10^8}$
= 1.6 × 10-7 T
So, the correct option is (D) : 1.6 × 10-7 T