Solveeit Logo

Question

Question: In a Periodic table the average atomic mass of Magnesium is given as \[24.312\text{ u}\].The average...

In a Periodic table the average atomic mass of Magnesium is given as 24.312 u24.312\text{ u}.The average value is based on their relative natural abundance on earth. The isotopes and their masses are 1224Mg(23.98504 u),1225Mg(24.98584 u){}_{12}^{24}\text{Mg}\left( 23.98504\text{ u} \right), {}_{12}^{25}\text{Mg}\left( 24.98584\text{ u} \right) and 1226Mg(25.9859 u){}_{12}^{26}\text{Mg}\left( 25.9859\text{ u} \right). The natural abundance of 1224Mg{}_{12}^{24}\text{Mg} is 78.99%78.99\% by mass. Calculate the abundance of two isotopes.

Explanation

Solution

Atoms that have the same number of protons but different numbers of neutrons are known as isotopes. Isotopes have different atomic masses. The relative abundance of an isotope is the percentage of atoms with a specific atomic mass found in naturally occurring sample
of an element.

Complete step by step answer:
Isotopes are defined as the atoms of the same element having the same number of protons but different number of neutrons. It means all elements have the same atomic number.
As given data in the questions are about isotopes of magnesium which is

ISOTOPESABUNDANCE (Y)ATOMIC MASS (M)
12Mg24_{12}\text{M}{{\text{g}}^{24}} 78.99 \text{ }78.99\text{ }23.98504\text{23}\text{.98504}
12Mg25 _{12}\text{M}{{\text{g}}^{25}}\text{ }x x\text{ }24.98584\text{24}\text{.98584}
12Mg26 _{12}\text{M}{{\text{g}}^{26}}\text{ }10078.99x=21.1x100-78.99-x=21.1-x25.98259\text{25}\text{.98259}
Y=100\sum{Y=100}

Atomic mass=24.312=24.312
Average atomic mass=YzY=\dfrac{\sum{Yz}}{\sum{Y}}
24.332=(78.99×23.98504)+(x×24.98584)+(21.01x)25.98254100\Rightarrow 24.332=\dfrac{\left( 78.99\times 23.98504 \right)+\left( x\times 24.98584 \right)+\left( 21.01-x \right)25.98254}{100}
2431.2=1894.58+24.98584x+545.8925.98254x\Rightarrow 2431.2=1894.58+24.98584x+545.89-25.98254x
24.312=2440.47.99675x\Rightarrow 24.312=2440.47-.99675x
.99675x=2440.472431.2\Rightarrow .99675x=2440.47-2431.2
x=9.27.99675=9.30\Rightarrow x=\dfrac{9.27}{.99675}=9.30
Thus 21.01x=21.019.30=11.7121.01-x=21.01-9.30=11.71
Therefore,
Relative abundance of 12Mg25 =9.30%_{12}\text{M}{{\text{g}}^{25}}\text{ }=9.30\%
Relative abundance of 12Mg26 =11.71%_{12}\text{M}{{\text{g}}^{26}}\text{ }=11.71\%

Note:
Basically Relative abundance on an isotope is the percentage of atoms with a specific atomic mass found in a naturally occurring sample of an element.